32.15 g of aluminum was dissolved in excess aqueous sodium hydroxide solution. Calculate the volume of gas released as a result of this reaction.
May 28, 2020 | Education|
Determine the amount of aluminum substance n = m / M, n (Al) = 32.15 g / 27g / mol = 1.19 mol
Substitute the resulting figure in the equation and make up the proportion
n (H2) = 1.19 mol * 3/2 = 1.786 mol
Find the gas volume V (H2) = VM * n (H2)
V = 22.4 L / mol * 1.786 mol = 40.0 L
The answer is written down to as many as 40
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