45 L of nitrogen, 15 L of oxygen and 60 L of carbon dioxide were mixed. Determine the volume fraction of gases in the resulting mixture.

Given: V (nitrogen) = 45 liters, V (oxygen) = 15 liters, V (carbon dioxide) = 60 liters.
Find: ϕ (nitrogen) – ?, ϕ (oxygen) – ?, ϕ (carbon dioxide) – ?.
Decision.
1st way
1. We calculate the volume of the mixture:
V (mixture) = V (nitrogen) + V (oxygen) + V (carbon dioxide) = 45 L + 15 L + 60 L = 120 L.
2. We calculate the volume fraction of nitrogen in a mixture of gases:
ϕ (nitrogen) = V (nitrogen) / V (mixture) = 45 l: 120 l = 0.375, or,
multiplying this value by 100%, we get 37.5%.
3. We calculate the volume fraction of oxygen in a gas mixture:
ϕ (oxygen) = V (oxygen) / V (mixture) = 15 l: 120 l = 0.125, or 12.5%.
4. We calculate the volume fraction of carbon dioxide in a mixture of gases:
ϕ (carbon dioxide) = V (carbon dioxide) / V (mixture) = 60 l: 120 l = 0.5, or 50%.
2nd way
1. Calculate the volume of the mixture:
V (mixture) = V (nitrogen) + V (oxygen) + V (carbon dioxide) = 45 l + 15 l + 60 l = 120 l.
2. We calculate the volume fraction of nitrogen in a mixture of gases:
ϕ (nitrogen) = V (nitrogen) / V (mixture) = 45 l: 120 l = 0.375, or,
multiplying this value by 100%, we get 37.5%.
3. We calculate the volume fraction of oxygen in a gas mixture:
ϕ (oxygen) = V (oxygen) / V (mixture) = 15 l: 120 l = 0.125, or 12.5%.
4. We calculate the volume fraction of carbon dioxide in a mixture of gases:
ϕ (carbon dioxide) = 100% -ϕ (nitrogen) -ϕ (oxygen) = 100% – 37.5% – 12.5% ​​= 50%.
Answer: ϕ (nitrogen) = 37.5%, ϕ (oxygen) = 12.5%, ϕ (carbon dioxide) = 50%.

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