A 24KB file is transferred over a connection in 80 seconds. Determine the size of the file (in Kbytes) that can be transferred over the same connection in 2 minutes.
Let’s calculate the data transfer rate over the channel: 24 Kbytes / 80 sec = 0.3 Kbytes / sec. Therefore, the size of a file that can be transferred in 2 minutes, that is, in 120 seconds, is 0.3 KB / sec 120 sec = 36 KB
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