A 4000 KB file is transferred over a connection within 2 minutes. Determine the size of the file (in KB) that can be transferred over this connection in 48 seconds. Please provide one number in your reply – the file size in KB. You do not need to write the units.
Let’s calculate the data transfer rate over the channel: 4000 KB / 120 sec = 100/3 KB / sec. Therefore, the size of a file that can be transferred in 48 seconds is 100/3 KB / sec * 48 sec = 1600 KB.
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