A drop with a charge of -8e is illuminated with ultraviolet rays. What was the charge of the drop when it lost: a) three electrons;
September 25, 2020 | Education
| A drop with a charge of -8e is illuminated with ultraviolet rays. What was the charge of the drop when it lost:
a) three electrons;
b) eight electrons;
c) eleven electrons?
a) calli had an excess of eight electrons, having lost three, the drop had an excess of five electrons, i.e. its charge became -5e.
b) the drop had an excess of eight electrons, having lost eight, the drop did not have an excess of electrons, i.e. its charge became 0.
c) the drop had an excess of eight electrons, having lost eleven, the calli had a deficiency of three electrons, i.e. its charge became equal to Ze.
