A horizontal force F is applied to a 2 kg bar lying on the table.The friction coefficient between the bar and the table is 0.4

A horizontal force F is applied to a 2 kg bar lying on the table.The friction coefficient between the bar and the table is 0.4,
a) What is the friction force acting on the bar if F = 5H?
b) What is the friction force acting on the bar if F = 10H?

a) The specified value of the force is less than the sliding friction force, so the bar remains at rest, and the static friction force will act on it, which balances the horizontal force applied to the bar. F = 5H. b) Ftp = uN = umg = 0.4 * 2kg “10N / kg = 8N

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