A solution of hydrochloric acid weighing 182.5 g and a mass fraction of 10% was added to the excess of magnesium sulfide.

A solution of hydrochloric acid weighing 182.5 g and a mass fraction of 10% was added to the excess of magnesium sulfide. Calculate the amount of gas evolved.

1) Let’s compose the reaction equation:
MgS + 2HCl = MgCl2 + H2S ↑
2) Calculate the mass and amount of the hydrochloric acid substance contained in the solution:
m (HCl) = (m (solution) ∙ ω) / 100% = (182.5 ∙ 10) / 100 = 18.25 g.
n (HCl) = m (HCl) / M (HCl) = 18.25 / 36.5 = 0.5 mol.
3) Determine the volume of released gas:
according to the reaction equation
n (H2S) = 0.5 ∙ n (HCl) = 0.5 ∙ 0.5 = 0.25 mol;
V (H2S) = n (H2S) ∙ Vm = 0.25 ∙ 22.4 = 5.6 l
Answer: 5.6 liters.

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