ABCD – parallelogram, the bisector of its angle B intersects side AD at point K; BC side = 11, segment KD = 3

ABCD – parallelogram, the bisector of its angle B intersects side AD at point K; BC side = 11, segment KD = 3. Find the perimeter of the parallelogram ABCD.

Since AD = BC, then AD = 11. Then AK = 11-3 = 8. The angles adjacent to the VK side in the triangle ABK are equal to each other. Therefore, this triangle is isosceles and AB = AK = 8. Therefore, the perimeter of the parallelogram ABCD is 38.

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