# After passing 6.72 liters of sulfur dioxide gas through the potassium hydroxide solution, 340.5 g of potassium sulfite solution

After passing 6.72 liters of sulfur dioxide gas through the potassium hydroxide solution, 340.5 g of potassium sulfite solution was obtained. Calculate the mass fraction of salt in the resulting solution. 1) Let’s compose the reaction equation:
SO2 + 2KOH = K2SO3 + H2O
2) Calculate the mass and amount of the potassium sulfite substance obtained as a result of the reaction:
n (SO2) = V (SO2) / Vm = 6.72 / 22.4 = 0.3 mol
according to the reaction equation
n (K2SO3) = n (SO2) = 0.3 mol;
3) Determine the mass fraction of potassium sulfite in the solution:
m (K2SO3) = n (K2SO3) ∙ M (K2SO3) = 0.3 ∙ 158 = 47.4 g.
ω (K2SO3) = (m (K2SO3) / m (solution)) ∙ 100% = (47.4 / 340.5) ∙ 100 = 13.92% Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.