Air separation produced 500 m3 of nitrogen. How many liters of oxygen and carbon dioxide were obtained from this?

Given: V (nitrogen) = 500m3, ϕ (nitrogen) = 78%, or 0.78, ϕ (oxygen) = 21%, or 0.21, ϕ (carbon dioxide) = 0.03%, or 0.0003 ,
Find: V (oxygen) – ?, V (carbon dioxide) -?
Decision.
From the formula for finding the volume fraction of nitrogen ϕ (nitrogen) = V (nitrogen) / V (air), we find the volume of air:
V (air) = V (nitrogen) / ϕ (nitrogen) = 500 m3: 0.78 = 641.03 m3.
We calculate the volume of oxygen:
V (oxygen) = ϕ (oxygen) ● V (air) = 641.03 m3 ● 0.21 = 134.6 m3.
We calculate the volume of carbon dioxide:
V (carbon dioxide) = ϕ (carbon dioxide) ● V (air) = 641.03 m3 ● 0.0003 = 0.192 m3.
Answer: V (oxygen) = 134.6 m3, V (carbon dioxide) = 0.192 m3.

Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.