Aluminum carbide weighing 86.4 g was dissolved in excess hydrochloric acid. Determine the mass of salt formed in this
| May 28, 2020 | Education
Reaction equation:
Al4C3 + 12HCl = 4AlCl3 + 3CH4 ↑
From the condition of the problem m (Al4C3) = 86.4 g. We find the amount of Al4C3 substance:
n (Al4C3) = m (Al4C3) / M (Al4C3) = 86.4 / 144 = 0.6 mol.
The resulting salt from the reaction is aluminum chloride. In the reaction equation, Al4C3 has a coefficient of 1, and AlCl3 has a coefficient of 4. Then the amount of aluminum chloride substance through the amount of aluminum carbide substance is expressed as follows:
n (AlCl3) = n (Al4C3) ⋅ 4/1 = 0.6 ⋅ 4/1 = 2.4 mol.
m (AlCl3) = n (AlCl3) ⋅ M (AlCl3) = 2.4 ⋅ 133.5 = 320.4 g.
Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.