Ammonia was passed through 126 g of a solution with a mass fraction of nitric acid of 30%, which completely reacted.

Ammonia was passed through 126 g of a solution with a mass fraction of nitric acid of 30%, which completely reacted. Determine the amount of ammonia reacted.

1) Let’s compose the reaction equation:
HNO3 + NH3 = NH4NO3
2) Calculate the mass and amount of the substance of the reacted nitric acid:
m (HNO3) = (ω (HNO3) ∙ m (solution)) / 100% = (30 ∙ 126) / 100 = 37.8 g
n (HNO3) = m (HNO3) / M (HNO3) = 37.8 / 63 = 0.6 mol.
3) Determine the amount of substance and the volume of the ammonia reacted:
n (NH3) = n (HNO3) = 0.6 mol
V (NH3) = n (NH3) ∙ Vm = 0.6 • 22.4 = 13.44 liters.
Answer: 13.44 liters.

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