Ammonia with a volume of 2.24 L was dissolved in 20 ml of 10% sulfuric acid (density 1.070 g / ml). Calculate the mass fraction

Ammonia with a volume of 2.24 L was dissolved in 20 ml of 10% sulfuric acid (density 1.070 g / ml). Calculate the mass fraction of ammonium sulfate in the final solution.

2NH3 + H2SO4 = (NH4) 2SO4
n (H2SO4) = (20 x 0.1 x 1.07) / 98 = 2.14 / 98 = 0.022 mol (deficient)
n (NH3) = 2.24 / 22.4 = 0.1 mol – in excess
m ((NH4) 2SO4) = 0.022 x (18 x 2 +96) = 2.9 g
m (solution) = 0.1 x 17 + 20 x 1.07 = 23.1 g
ω ((NH4) 2SO4) = 2.9 / 23.1 x 100% = 12.5%
Answer: the mass fraction of ammonium sulfate in the final solution is 12.5%.

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