An 80K file is transferred over some connection at 2048 bits per second. Determine the file size (in KB) that can be transferred in the same amount of time over another connection at 768 bits per second. Please provide one number in your reply – the file size in KB.
Let’s define the transmission time:
80 KB / 2048 bits per second = (80 * 1024 * 8 bits) / (2048 bits per second) = 40 * 8 seconds.
Let’s calculate the file size:
40 * 8 seconds * 768 bits per second = 30720 * 8 bits = 30 KB.
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