An article typed on a computer contains 16 pages, each page contains 40 lines, each line contains 40 characters. Determine the information volume of the article in Windows-1251 encoding, in which each character is encoded in 8 bits.
Let’s find the number of characters in the article:
16 * 40 * 40 = 2 ^ 10 * 25.
One character is encoded in one byte, 2 ^ 10 bytes are 1 kilobyte, therefore the information volume of the article is 25 Kbytes.
Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.