An article typed on a computer contains 16 pages, each page contains 40 lines, each line contains 40 characters.

An article typed on a computer contains 16 pages, each page contains 40 lines, each line contains 40 characters. Determine the information volume of the article in Windows-1251 encoding, in which each character is encoded in 8 bits.

Let’s find the number of characters in the article:
16 * 40 * 40 = 2 ^ 10 * 25.
One character is encoded in one byte, 2 ^ 10 bytes are 1 kilobyte, therefore the information volume of the article is 25 Kbytes.

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