# An excess of dilute sulfuric acid was added to 150 g of sodium carbonate solution and the solution was heated until gas evolution ceased

An excess of dilute sulfuric acid was added to 150 g of sodium carbonate solution and the solution was heated until gas evolution ceased. A total of 4.48 liters of gas were released. Calculate the mass fraction of sodium carbonate in the original solution. 1) Let’s compose the reaction equation:
Na2CO3 + H2SO4 = Na2SO4 + CO2 ↑ + H2O
2) Calculate the amount of substance and the mass of sodium carbonate:
n (CO2) = V (CO2) / Vm = 4.48 / 22.4 = 0.2 mol.
according to the reaction equation
n (Na2CO3) = n (CO2) = 0.2 mol
m (Na2CO3) = n (Na2CO3) ∙ M (Na2CO3) = 0.2 ∙ 106 = 21.2 g.
3) Determine the mass fraction of sodium carbonate in the solution:
ω (Na2CO3) = (m (Na2CO3) / m (solution)) ∙ 100% = (21.2 / 150) ∙ 100 = 14.13% Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.