As a result of the reaction of aluminum with hydrochloric acid, 0.4 mol of salt was formed. How much hydrogen was released?

2Al + 6HCl = 2AlCl3 + 3H2
the number of moles of hydrogen is 1.5 times the number of moles of aluminum, which means it is 0.4 * 1.5 = 0.6 mol. The volume of hydrogen is 0.6 * 22.4 = 13.44 L

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