# Calculate molar, molar concentration of equivalent in titer of 36% hydrochloric acid solution

M (HCl) = 36.5 g / mol;
HCl is a monobasic acid, then feq (HCl) = 1/1 = 1;
according to tabular data, the density of a 36% HCl solution is 1.179 g / ml.
Find the mass of the solution, we get:
m (p-pa) = V. p (p-pa) = [1000. 1,179] = 1179 g.
Calculate the mass of HCl, we get:
m (HCl) = w% (HCl). m (p-pa) / 100% = (36. 1179) / 100 = 424.44 g.
Find the molarity of the solution, we get:
CM (HCl) = m (HCl) / M (HCl) = 424.44 / 36.5 = 11.65 mol / L.
Since feq (HCl) = 1, then SE (HCl) = CM (HCl) = 11.65 mol / L.
We find the titer of hydrochloric acid solution, we get:
T (HCl) = m (HCl / V = 424.44 / 1000 = 0.4242 g / ml.
Answer: CM (HCl) = 11.65 mol / L; SE (HCl) = 11.65 mol / L; T (HCl) = 0.4242 g / ml

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