Calculate the amount of chlorine needed to completely oxidize 12.7 g of iron dichloride.

2FeCl2 + Cl2 = 2FeCl3
V (chlorine) = 22.4 * 0.5n (iron dichloride) = 22.4 * 0.5 * 12.7 / (56 + 35.5 * 2) = 1.12 L
Answer: 1.12 L

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