Calculate the mass of oxygen needed to completely burn 6.72 L of hydrogen sulfide.

Reaction equation:

2H2S + 3O2 = 2SO2 + 2H2O

From the condition we find the amount of hydrogen sulfide substance:

n (H2S) = 6.72 / 22.4 = 0.3 mol;

In the reaction equation, oxygen has a coefficient of 3 and hydrogen 2. It follows that the amount of substance that has reacted with oxygen through the amount of hydrogen sulfide is expressed as follows:

n (O2) = n (H2S) ⋅ 3/2 = 0.45 mol.


m (O2) = M (O2) ⋅ n (O2) = 32 * 0.45 = 14.4 g

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