Calculate the mass of salt obtained by the interaction of 200 g of a solution of sulfuric acid with a mass fraction of 20% with a solution of sodium hydroxide
M (H2SO4) = 98 g / mol;
M (Na2SO4) = 142 g / mol.
We find the mass of sulfuric acid:
m (H2SO4) = 200. 0.2 = 40 g.
The reaction equation has the form:
40 g x g
H2SO4 + 2NaOH = Na2SO4 + 2H2O
98 g 142 g
We calculate the mass of salt from the proportion, we get:
40: x = 98: 142;
x = (40.142) / 98 = 57.96 g or 58 g.
Answer: 58 g.
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