Calculate the mass of sediment formed by the interaction of an excess of barium nitrate solution with a solution containing 3.92 g of sulfuric acid.
Compose a reaction equation
Ba (NO3) 2 + H2SO4 = BaSO4 + 2HNO3
Calculate the amount of sulfuric acid substance 3.92g / 98g / mol = 0.04 mol
Calculate the amount of precipitate substance (BaSO4) = 0.04 mol (equal to the amount of sulfuric acid substance)
Calculate the mass of the precipitate (BaSO4) m = M * n (amount of substance) m = 0.04 mol * 233 g / mol = 9.3 g
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