Calculate the mass of the precipitate that will precipitate when an excess of potassium carbonate interacts with 31.4 g

Calculate the mass of the precipitate that will precipitate when an excess of potassium carbonate interacts with 31.4 g of a barium nitrate solution with a mass fraction of the latter of 10%.

1) Let’s compose the reaction equation:
K2CO3 + Ba (NO3) 2 = BaCO3 ↓ + 2KNO3
2) Calculate the mass and amount of the barium nitrate substance in the solution:
m (Ba (NO3) 2) = (m (solution) ∙ ω) / 100% = (31.4 ∙ 10) / 100 = 3.14 g.
n (Ba (NO3) 2) = m (Ba (NO3) 2) / M (Ba (NO3) 2) = 3.14 / 261 = 0.012 mol.
3) Determine the mass of the precipitated substance:
according to the reaction equation
n (BaCO3) = n (Ba (NO3) 2) = 0.012 mol;
m (BaCO3) = n (BaCO3) ∙ M (BaCO3) = 0.012 ∙ 197 = 2.36 g.
Answer: 2.36 g.