Calculate the volume (n.o.) of oxygen required for the complete combustion of 4.6 g of ethanol.

bystudin | May 28, 2020 | Education

2C2H5OH + 6O2 = 4CO2 + 6H2O
V (oxygen) = 3V (ethanol) = 3 * 4.6 / (12 * 2 + 5 + 16 + 1) * 22.4 = 6.72 L
Answer: 6.72 L

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