# Cyclists travel towards each other at the same speed along a 500 m long tunnel and meet at a distance of 150 m from

**Cyclists travel towards each other at the same speed along a 500 m long tunnel and meet at a distance of 150 m from the southern end of the tunnel, a cyclist traveling south meets a car at the southern end of the tunnel, and a cyclist traveling north meets the same car catches up at the northern end of the tunnel, How many times is the speed of a car faster than the speed of a cyclist?**

Cyclists meet at a distance from the south side of the tunnel. Since their speeds are the same, the cyclist traveling north traveled 150m until the second cyclist met the car. This means that the cyclist traveling north traveled the remaining 200m in the same time as the motorist traveled the entire tunnel.

tv = 200 / v; tа = 200 / vа; 200 / vv = 200 / va, va / vv = 500/200 = 2.5. Answer: The speed of a motorist is 2.5 times that of a cyclist.