# Determine the mass fractions of sulfuric and nitric acids in the solution if, when an excess of barium chloride was added to 200 g

**Determine the mass fractions of sulfuric and nitric acids in the solution if, when an excess of barium chloride was added to 200 g of this solution, 46.6 g of precipitate was released, and to neutralize the resulting solution, 50 ml of a 30% sodium hydroxide solution with a density of 1.33 g / ml were required …**

H2SO4 + BaCl2 → BaSO4 ↓ + 2HCl

HNO3 + NaOH → NaNO3 + H2O

m (BaSO4) = 46.6 g

n (BaSO4) = 46.6 / 233 = 0.2 mol

n (NaOH) = (50 x 0.3 x 1.33) / 40 = 0.5 mol

⇒ n (H2SO4) = 0.2 mol

n (HNO3) = 0.5 mol

⇒ m (H2SO4) = 0.2 x 98 = 19.6 g

m (HNO3) = 0.5 x 63 = 31.5 g

ω (H2SO4) = 19.6 / 200 x 100% = 9.8%

ω (HNO3) = 31.5 / 200 x 100% = 15.75%

Answer: the mass fractions of sulfuric and nitric acid in the solution are respectively equal to 9.8% and 15.75%.