Determine the mass of the salt, as well as the amount of ammonium cations and sulfate ions formed in an aqueous solution

Determine the mass of the salt, as well as the amount of ammonium cations and sulfate ions formed in an aqueous solution when an excess of ammonia reacts with 20 ml of 10% sulfuric acid (density 1.070 g / ml).

2NH3sur + H2SO4 → (NH4) 2SO4
n (H2SO4) = (20 x 0.1 x 1.070) / 98 = 0.022 mol
n ((NH4) 2SO3) = n (H2SO4) = 0.022 mol
m ((NH4) 2SO4) = 0.022 x (18 x 2 + 32 +64) = 2.9 g
(NH4) 2SO4 → 2NH4 + + SO4²‾
n (NH4 +) = V ((NH4) 2SO4) x 2 = 0.044 mol
n (SO4²‾) = n ((NH4) 2SO4)
Answer: the mass of the salt (ammonium sulfate) is 2.9 g, the amount of ammonium cations is 0.044, the amount of sulfate ions is 0.022 mol.

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