Determine the mass of the salt formed by the reaction of 3.36 liters of ammonia with 10 ml of 2% sulfuric acid (density 1.070 g / ml).

2NH3 + H2SO4 = (NH4) 2SO4
n (NH3) = 3.36 / 22.4 = 0.15 mol – in excess
n ((H2SO4) = (10 x 0.02 x 1.07) / 98 = 0.0022 mol – deficient
m ((NH4) 2SO4 = 0.0022 x (18×2 + 96) = 0.3 g
Answer: the mass of the formed salt is 0.3 g.

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