Determine the orbital period of the asteroid Lutetia if its semi-major axis is 2.43 AU.

To solve the problem, we will use Kepler’s III law: T1 / T2 = a1 / a2. We take the Earth as the second body, assuming that T2 = 1 year and a2 = 1 a. e. Then the formula will take the form: T1 = a1 * T1 = (2.43) ^ 3 = 14.35; T = 3.8 (years).

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