# Determine the volume fraction of ammonia in its gas mixture with air, if it is known that 2.913 liters of a 4.9% sulfuric

**Determine the volume fraction of ammonia in its gas mixture with air, if it is known that 2.913 liters of a 4.9% sulfuric acid solution with a density of 1.03 g / ml (the reaction product is a medium salt) were consumed to neutralize 150 liters of this mixture.**

1) Let’s compose the reaction equation:

2NH3 + H2SO4 = (NH4) 2SO4

2) Calculate the mass and amount of sulfuric acid substance:

ρ = m / V

V (H2SO4) = 2.913 L = 2913 ml

m (solution) = ρ (H2SO4) ∙ V (H2SO4) = 1.03 ∙ 2913 = 3000 g.

m (H2SO4) = (m (solution)) ∙ ω (H2SO4) / 100% = 3000 ∙ 4.9 / 100 = 147 g.

n (H2SO4) = m (H2SO4) / M (H2SO4) = 147/98 = 1.5 mol.

3) Determine the amount of substance and the volume fraction of ammonia:

According to the reaction equation:

n (NH3) = 2n (H2SO4) = 2 ∙ 1.5 = 3 mol

V (NH3) = n (NH3) ∙ Vm = 3 • 22.4 = 67.2 liters.

φ (NH3) = V (NH3) / V (mixture) = 67.2 / 150 = 0.448 = 44.8%

Answer: 44.8%