Determine what file size can be transferred over a 10 Kbps channel in 5 seconds?

V = 10 kbps,
t = 5 s.
Find: I -?
Decision:
I = V * t = 10 * 1024 = 10 240 bits * 5 sec = 51 200 bits / 8 = 6400 bytes / 1024 =
= 6.25 KB
Answer: 6.25 KB

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