During the great opposition of Jupiter on September 21, 2010, it was at a distance of 3.95 AU from Earth.

During the great opposition of Jupiter on September 21, 2010, it was at a distance of 3.95 AU from Earth. The angular diameter of the planet was 50 “. Calculate the linear diameter of Jupiter.

It is necessary to express the angular diameter in radian measure: 50 “= 50 * 1” = 50 • 1/206265 rad = 2.4 • 10 ^ ~ 4 rad;
d = Dp = 3.95 * 1.5 * 10 ^ 8 * 2.4 * 10 ^ ~ 4 = 1.42 * 10 ^ 5km.

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