During the reduction of copper (II) oxide with ammonia, 24 g of metal were obtained. Ammonia consumed equals

bystudin | May 28, 2020 | Education

3CuO + 2NH3 = 3Cu + N2 + 3H2O
3n (NH3) = 2n (Cu)
3V (NH3) / 22.4 = 2m (Cu) / M (Cu)
3V (NH3) / 22.4 = 2 * 24/64
V (NH3) = 2 * 24 * 22.4 / (3 * 64) = 5.6 L

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