Find the azimuth and the moment of rise of a Ophiuchus (a = 17h31m, b = +13) in Petersburg (φ = +60).

The azimuth of sunrise will be РSCM1 = A = 117o East, and the hourly angle of sunrise will be РKFM1 = t = 248 = 16h32m. Hence, knowing that a given star has a = 17h31m, we find that sidereal time at the moment of rising will be s = t + a = 16h32m + 17h31m = 10h3m.

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