Find the value of the acute angle of the parallelogram ABCD if the bisector of angle A forms an angle of 1 ° with side BC.

∠BCA = ∠DAC = 1 ° (as these are cross-angles)
And since AC is a bisector, ∠BAC = ∠DAC = 1 °.
∠A = ∠BAC + ∠DAC = 1 ° + 1 ° = 2 °
Answer: 2

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