# For titration of 5 ml of potassium carbonate solution, 13 ml of hydrochloric acid solution with C (1 / z HCl)

**For titration of 5 ml of potassium carbonate solution, 13 ml of hydrochloric acid solution with C (1 / z HCl) = 0.095 mol / L was consumed. Calculate C (1 / z K2CO3), T (K2CO3) and m (K2CO3) in solution**

The reaction equation has the form:

K2CO3 + 2HCl = 2KCl + H2O + CO2 ↑

M (K2CO3) = 138 g / mol.

a) Calculation of C (1 / z K2CO3)

The number of moles of equivalents of a substance can be calculated through the mass m (B) of substance B:

C (1 / z K2CO3) = m (B) / M (1 / zB)

To calculate according to the titration results, we use the mathematical expression of the consequence of the law of equivalence (the so-called rule of proportionality):

CE (A). V (A) = CE (B). V (B)

Where

CE (A) and CE (B) – normal concentrations of equivalents of substances K2CO3 and HCl, mol / l; VA) and V (B) – volumes of solutions of substances K2CO3 and HCl.

Then

normality CE (K2CO3) = [CE (HCl). V (HCl)] / V (K2CO3) = (0.095. 13) / 5 = 0.247 mol / L.

b) Find the mass of K2CO3, we get:

m (K2CO3) = CE (K2CO3). [M (K2CO3) / 2]. [(5/1000)] = [0.247. (138/2) / (5/1000] = 0.085g.

c) Calculate the titer T (K2CO3), we get:

T (K2CO3) = m (K2CO3) / V (K2CO3) = 0.085 / 5 = 0.017 g / ml.

Answer: CE (K2CO3) = 0.247 mol / L; m (K2CO3) = 0.085g; T (K2CO3) = 0.017g / ml