# From a solution of aluminum chloride weighing 110 g and a mass fraction of salt of 10%, 10 g of water was evaporated

From a solution of aluminum chloride weighing 110 g and a mass fraction of salt of 10%, 10 g of water was evaporated and 5 g of the same salt was added. Mass fraction of salt in the resulting solution is equal to ω = m substance / (m solution)
Find the mass of aluminum chloride from the first solution of m substance = m solution * ω
m substance = 110g * 0.1 = 11g
m water = m solution – m substances = 110-11 = 99 g
By condition, 10 g of water was evaporated.
Next, 5 g of salt is added to the solution.
Thus, the final solution will contain:
water 99-10 = 89 g
aluminum chloride = 11 + 5 = 16 g
total weight = 89 + 16 = 105 g
We substitute the values in the formula ω = 16 * 100% / 105 = 15.2% Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.