How many grams of 30% sulfuric acid must be taken to get 200 g of a 12% solution of H2SO4

bystudin | May 28, 2020 | Education

200 g of 12% acid contains 200 * 0.12 = 24 g of acid
We compose the proportion:
1 g (30% acid) – 0.3 g acid
x g of 30% acid – 24 g of acid
Solving it, we get that x = 24 / 0.3 = 80 g

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