How many grams of 40% alkali should be taken to get 300 g of 8% alkali?

bystudin | May 28, 2020 | Education

300 g of 8% alkali contains 300 * 0.08 = 24 g of alkali
We compose the proportion:
1 g (40% alkali) – 0.4 g alkali
x g of 40% alkali – 24 g of alkali
Solving it, we get that x = 24 / 0.4 = 60 g

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