How many grams of water should be added to 300 g of a 22% solution of acetic acid to obtain a 9% solution?
ω = m (substance) / m (solution)
Find the mass of acid m = 300 * 0.22 = 66 g
Find the mass of the final solution m (final solution) = m (substance) / ω = 66 / 0.09 = 733 g
m (water) = m (final solution) – m (initial solution) = 733-300 = 433 g
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