How much carbon dioxide is formed when 32 liters of ethane are burned in excess oxygen?

We write the reaction equation:

2C2H6 + 7O2 → 4CO2 + 6H2O

Calculate the amount of ethane:

n (C2H6) = V (C2H6) / Vm = 32 / 22.4 = 1.429 mol

In the reaction equation, C2H6 has a coefficient of 2, and CO2 is a factor of 4. This means that the amount of CO2 substance through the amount of C2H6 can be as follows:

n (CO2) = n (C2H6) ⋅ 4/2 = 2.858 mol

V (CO2) = n (CO2) ⋅ Vm = 2.858 ⋅ 22.4 = 64 L

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