We write the reaction equation:
2C2H6 + 7O2 → 4CO2 + 6H2O
Calculate the amount of ethane:
n (C2H6) = V (C2H6) / Vm = 32 / 22.4 = 1.429 mol
In the reaction equation, C2H6 has a coefficient of 2, and CO2 is a factor of 4. This means that the amount of CO2 substance through the amount of C2H6 can be as follows:
n (CO2) = n (C2H6) ⋅ 4/2 = 2.858 mol
V (CO2) = n (CO2) ⋅ Vm = 2.858 ⋅ 22.4 = 64 L
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