How much hydrogen sulfide was released when 0.3 mol of iron (II) sulfide reacted with an excess of hydrochloric acid?
Compose a reaction equation
FeS + 2HCl = FeCl2 + H2S
Calculate the amount of gas substance (H2S) = 0.3 mol (the amount of substance of iron sulfide)
Calculate the volume of gas (Н2S) V = Vm * n (amount of substance) V = 0.3 mol * 22.4 l / mol = 6.72 l
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