How much is the binding energy of the nucleus of an atom of the carbon isotope 15 6C greater than the binding energy of the nucleus

How much is the binding energy of the nucleus of an atom of the carbon isotope 15 6C greater than the binding energy of the nucleus of its other isotope 12 6C, if the difference in the masses of the corresponding atoms of these isotopes is 3.0106 amu?

Isotope 12 6C: E1 = m1 * 931.5 = (6 * Mp + 6 * Mn – My) * 931.5 = (6 (1.00728 + 1.00866) -12) * 931.5 = 0.09564 * 931.5 = 89.08866 MeV
Isotope 15 6C: E2 = m2 * 931.5 = (6Mp + 9Mn – My) * 931.5 = (6 * 1.00728 + 9 * 1.00866 – (12 + 3.0106)) * 931.5 = 0.11102 * 931.5 = 103.41513 MeV
E2 – E1 = 103.41513 – 89.08866 = 14.32647 MeV