How much oxygen is needed for the catalytic oxidation of 16 liters of ammonia?

bystudin | May 28, 2020 | Education

Reaction equation:

4NH3 + 5O2 -> 4NO + 6H2O

From the condition V (NH3) = 16 liters. Calculate the amount of ammonia:

n (NH3) = V (NH3) / Vm = 16 / 22.4 = 0.7143 mol;

NH3 in the equation has a coefficient of 4, and O2 has a coefficient of 5. Thus, the amount of oxygen substance through the amount of ammonia substance is expressed as follows:

n (O2) = n (NH3) ⋅ 5/4 = 0.7143 ⋅ 5/4 = 0.8929 mol

Hence:

V (O2) = n (O2) ⋅ M (O2) = 0.8929 ⋅ 22.4 = 20 l.

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