In 150 liters of a mixture of sulfur oxide (IV) with carbon monoxide (IV), the volume fraction of the latter is 15%.

In 150 liters of a mixture of sulfur oxide (IV) with carbon monoxide (IV), the volume fraction of the latter is 15%. How many liters of each of the oxides are in the mixture?

Given: V (mixture) = 150 l, ϕ (CO2) = 15%, or 0.15.
Find: V (SO2) – ?, V (СО2) -?
Decision.
1st way
1. From the formula for finding the volume fraction ϕ (СО2) = V (СО2) / V (mixture), we find the volume of carbon monoxide (IV):
V (СО2) = ϕ (СО2) • V (mixture) = 0.15 • 150 liters = 22.5 liters.
2. Calculate the volume of sulfur oxide (IV):
V (SO2) = V (mixture) – V (CO2) = 150 l – 22.5 l = 127.5 l.
2nd way
1. Calculate the volume of carbon monoxide (IV):
V (СО2) = ϕ (СО2) • V (mixture) = 0.15 • 150 liters = 22.5 liters.
2. Calculate the volume of sulfur oxide (IV):
V (SO2) = ϕ (SO2) • V (mixture) = (1-ϕ (CO2)) • V (mixture) = (1-0.15) • 150 L = 0.85 • 150 L = 127.5 l.
Answer: V (CO2) = 22.5 liters, V (SO2) = 127.5 liters.

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