In a place lying on the Earth’s equator (latitude j = 0њ), a star was observed with azimuth a = 40њ Ost and zenith distance z = 20њ.
| November 10, 2020 | Education
In a place lying on the Earth’s equator (latitude j = 0њ), a star was observed with azimuth a = 40њ Ost and zenith distance z = 20њ. Find the hour angle t and declination d of this star.
Hour angle t = AND EQK = 340њ.
Declination d = AND RM = -15њ.
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