In a random experiment, a symmetric coin is thrown twice. Find the probability that the eagle will not fall even once.

Since the coin is thrown twice, then, as in Problem 1, the number of possible elementary outcomes is n = 4. Favorable outcomes of the event A = {the eagle does not fall out once} correspond to option No. 4 of the experiment (see the table in task 1). This option is one, then m = 1.
We find the probability of the event P (A) = m / n = 1/4 = 0.25

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