# In an excess of hydrochloric acid, 2.11 g of ore containing 71% iron (II) carbonate was dissolved. Determine the amount of carbon

In an excess of hydrochloric acid, 2.11 g of ore containing 71% iron (II) carbonate was dissolved. Determine the amount of carbon dioxide released during this. 1) Let’s compose the reaction equation:
FeCO3 + 2HCl = FeCl2 + H2O + CO2 ↑
2) Determine the mass of pure iron carbonate and its amount of substance:
m (FeCO3) = (m (ore) ∙ ω) / 100% = (2.11 ∙ 71) / 100 = 1.50 g.
n (FeCO3) = m (FeCO3) / M (FeCO3) = 1.50 / 116 = 0.013 mol.
3) Let’s calculate the amount of the substance of the released carbon dioxide and its volume:
according to the reaction equation
n (CO2) = n (FeCO3) = 0.013 mol;
V (CO2) = n (CO2) ∙ Vm = 0.013 ∙ 22.4 = 0.29 l. Remember: The process of learning a person lasts a lifetime. The value of the same knowledge for different people may be different, it is determined by their individual characteristics and needs. Therefore, knowledge is always needed at any age and position.