In the process of isobaric cooling, the volume of ideal gas decreased by 2 times. What is the final gas temperature

In the process of isobaric cooling, the volume of ideal gas decreased by 2 times. What is the final gas temperature if its initial temperature is 819 ° C? The gas mass is constant.

V2 / V1 = T1 / T2;
T2 = T1 * (V2 / V1);
V2 = V1 / 2;
T2 = T1 / 2;
T1 = 819 + 273 = 1092K;
T2 = 546 – 273 = 273 (Degrees Celsius).

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