# In triangle ABC, AC = 15, BC = 5√7, angle C is 90 °. Find the radius of the circumscribed circle of this triangle

May 31, 2020 | Education

| The triangle ABC is rectangular, then by the Pythagorean theorem:

AB2 = AC2 + BC2

AB ^ 2 = 15 ^ 2 + (5√7) ^ 2

AB ^ 2 = 225 + 25 * 7

AB ^ 2 = 400

AB = 20

Since the triangle ABC is right-angled, this means that the center of the circle is in the middle of the hypotenuse (by the theorem on the circumscribed circle).

Then R = AB / 2 = 20/2 = 10

Answer: R = 10

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